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In Reply to: Ha Ha! - Duke vs John - who wins? posted by cawson@onetel.com on March 10, 2019 at 06:09:52:
The question piqued my interest and a dove straight in without noticing John's answer. He is saying that at the output level to give 4W into 8ohms if you half the load to 4 ohms the power will double as it is a classA/B amplifier that can increase output current on demand, within the limitations of its power supply. But if it is was a 4W into 8 ohm class A amplifier the maximum output current is fixed and as the load decreases the amp cannot supply more current to maintain the voltage swing and you would get current clipping. The most power it could supply into 4ohms before clipping would be 2W. So the classA/B will double the power into 4ohms but now it leave the classA region at 2W instead of 4W.
Regards,
13DoW
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Follow Ups
- It is not a contest and we're both right - 13th Duke of Wymbourne 13:21:46 03/10/19 (9)
- RE: It is not a contest and we're both right - John Elison 18:59:34 03/10/19 (6)
- "However, the amplifier will still maintain 5.657-volts at its speaker terminals when the load changes from 8" - Caucasian Blackplate 08:46:01 03/11/19 (0)
- RE: It is not a contest and we're both right - 13th Duke of Wymbourne 21:18:06 03/10/19 (4)
- Interesting! - John Elison 05:44:55 03/11/19 (3)
- Addendum - 13th Duke of Wymbourne 19:21:59 03/11/19 (2)
- RE: Addendum - John Elison 12:52:46 03/12/19 (1)
- A summary - 13th Duke of Wymbourne 18:47:37 03/12/19 (0)
- RE: It is not a contest and we're both right - George6 17:40:08 03/10/19 (1)
- RE: It is not a contest and we're both right - 13th Duke of Wymbourne 18:31:26 03/10/19 (0)