|
Amp/Preamp Asylum Looking for a new Amp or Preamp? If you're after tubes, post over here. |
|
|
|
Amp/Preamp Asylum Looking for a new Amp or Preamp? If you're after tubes, post over here. |
|
In Reply to: Class A power in A/B amp question posted by George6 on March 9, 2019 at 18:23:50:
The class A/B power is determined by V^2/R so when R halves the power doubles. The class A region will be limited by the DC bias current in the output stage. As P= I^2*R, as R halves the class A power in the load also halves and you will go into class AB at half the voltage swing you did in the 8 ohm case.i.e. For 4Wrms into 8 ohms that is an rms current of 0.707A and a peak current of +/- 1A. So the amp output stage must be biased at 1A, at least. When the load is 4 ohms the voltage that +/- 0.707Arms can generate across the load is +/- 2.82 Vrms.
P = V^2/R so the class A power is 2.82*2.82/4 = 2Wrms
Or we can arrived at the same destination using P = I^2*R = 0.707*0.707*4 = 2W.Regards
13DoW
Edits: 03/09/19
This post is made possible by the generous support of people like you and our sponsors:
Follow Ups
- RE: Class A power in A/B amp question - 13th Duke of Wymbourne 20:13:27 03/09/19 (1)
- +1 nt - Caucasian Blackplate 10:10:12 03/10/19 (0)
Top of Page ]
[ Contact Us ]
[ Support/Wish List ]
[ Copyright © 2024, Audio Asylum, all rights reserved ]
