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205.225.146.106
I have a good size potted power transformer having the following secondary windings but without any specs. I want to use the 390v+390v for a SE amp. What is the easy way to figure out the max current of this winding?Thanks for your help in advance
6.3v
6.3v
6.3v
510v
390v+390v
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Measure secondary voltages without load. They will be higher than rated. Then disconnect the primary and measure DC resistance of each winding. Calculate voltage drop for each winding, which will be the difference between the no-load and rated voltages. Divide this voltage drop by winding's DCR, and this will yield the rated current. For example, if the no-load voltage of a 6.3 V winding is 7.0 V and its DC resistance is 0.7 Ohms, the rated current is (7.0-6.3)/0.7 = 1 A.Keep in mind that old transformers were designed for 115 V line, and todays voltages are about 125 V. So, if it is an old transformer, you should apply 115 V from a variac for no-load voltage measurements.
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If this is not practical, then estimate it by adding up all the volt-amperes of the secondary winding loads yhou intend to use and estimating the core volt-ampere capacity. Try to keep the operating load well under the maximum capacity of the core.To estimate the core capacity, take the core dimensions and compare them to a catalog listing of similar style and size transformers.
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