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RE: Can I bypass parallel Caps

Using two equal value capacitors in series + to + or - to - makes one bipolar capacitor of half the value of one single capacitor.

Capacitors in series values add like resistors in parallel.

1/(1/C1+1/C2) 1/(1/470+1/470)=235uF

So if C448 in your diagram is intended to be a 470uF bipolar you need to use two pairs of 2 470uF in series, in parallel. That would be use all four C446, C447, C448, C449.

As far as bypassing treat the two (or four) as one single capacitor.

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  • RE: Can I bypass parallel Caps - Tweekeng 10:12:21 06/16/12 (0)


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