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RE: DC voltage drop across choke vs resistor!!!

My confusion is that with everything in place with only only one power supply to one tube no other branches the current should be constant. So a resistor in series can be measured for voltage drop then ohms law we have the current in circuit or through the tube.

The question is in regards to why when you measure the voltage drop across a choke with known DC resistance it is different than a resistor with the same resistance.

So in the above example using the voltage drop the choke shows we have a 18 ma circuit and the voltage drop across the resistor shows a 16 ma circuit. This is b+ to a tube circuit.

So I am guessing the DC circuit is seeing the choke as more than just its resistance. My question is why.


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