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In Reply to: Re: How can that work well? posted by Triode Kingdon on January 26, 2004 at 07:37:07:
Hello TK,Regarding the first point, I thought we were talking only about the secondary load. But take your point about a 12au7 having a tougher time than a 10ohm source for a given tx and load.
Completely agree with your point about inter-winding capacitance, which in conjunction with the miller cap of the driven stage is, to my mind, the prime engineering argument for using damping resistors or zobel networks.
But I still don't follow that there must be appreciable current flow for the tx to operate "correctly"; you don't define what you mean by this - do you mean that, for eg a 1:1 tx, that Vout will equal Vin (neglecting capacitive effects)?
Alternatively, what happens to the transformer action if the secondary is truly unloaded? I've been scratching my head on this one - does Faraday say the voltages will be the same despite differing current flows (magnetisation current, and 0, for the pri and sec respectively)?
All that neglects capacitance of course!
cheers
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Follow Ups
- Re: How can that work well? - vry 08:50:12 01/26/04 (0)
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