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RE: update 2

"Well I gave that a try but I must have done something wrong because I came up with a voltage of 48vdc."

First of all, the voltage you should be measuring across the 8 ohm load resistor is ac, not dc. (You can't get dc out of a transformer.) Trying to guess what you actually meant to type, one possibility is that you meant 48v pp (that is, 48 volts peak-to-peak of the 1KHz sine wave). That would correspond to 48/( 2 * sqrt2) volts RMS, which is about 17 VRMS. This would imply a power of 36 watts. That seems implausibly high, though.

However, there are too many uncertainties and guesses involved, with trying to estimate what you meant to type when you wrote 48vdc. Perhaps you could clarify?



Edits: 02/18/19

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