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RE: If the signal goes in both caps they must divide.

But this, I think, is a case where the water analogy falls apart. I don't think you could in theory put your finger on one electron and say that this one went through capacitor A and that one went through capacitor B. All the signal goes through both capacitors, is how I think of it. In fact, one might support that position by the observation that the capacitors in parallel provide a net additive capacitance across the whole signal. Somehow, the signal is in both capacitors at once.

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