In Reply to: How about some o'scope pics at C1 or L1 and so forth posted by wheezer on August 23, 2012 at 08:21:41:
PSUD2 does a good job of predicting currents.
Here's the charging current through L1 when L1 has an inductance lower than critical.
Question. In the above example, what supplies the voltage and current to the circuit, when using a LCLC PS filter, while the diodes are both off?
Answer. The charge stored in the filter.
Here's the charging current through L1 when L1 meets critical inductance.
Question. In the above example, what supplies the voltage and current to the circuit, when using a LCLC PS filter, when the diodes never turn off?
BTW Both supplies are delivering about 60ma at similar voltages. Notice how high the charging current is in the first example. This is because of the off time. It has to make up for the off time.
Tre'
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Follow Ups
- Not o'scope pics but... - Tre' 09:00:48 08/23/12 (13)
- RE: Not o'scope pics but... - wheezer 17:01:47 08/23/12 (0)
- Good job! - mikeyb 09:50:31 08/23/12 (11)
- RE: Good job! - Tre' 10:05:03 08/23/12 (10)
- Thanks! - mikeyb 10:14:36 08/23/12 (9)
- RE: Thanks! - drlowmu 18:52:49 08/23/12 (8)
- Hardly ... - mikeyb 05:45:51 08/24/12 (1)
- RE: Hardly ... - drlowmu 15:37:32 08/24/12 (0)
- RE: Are you going to debunk Ohm's Law?? - Ray Moth 19:14:50 08/23/12 (5)
- RE: Are you going to debunk Ohm's Law?? - drlowmu 19:39:21 08/23/12 (4)
- RE: Are you going to debunk Ohm's Law?? - Ray Moth 20:26:08 08/24/12 (3)
- RE: Are you going to debunk Ohm's Law?? - drlowmu 22:51:31 08/25/12 (2)
- RE: Are you going to debunk Ohm's Law?? - Ray Moth 02:56:45 08/26/12 (1)
- RE: Are you going to debunk Ohm's Law?? - drlowmu 07:57:01 08/26/12 (0)