In Reply to: what triode and transistor to use for a shunt regulator circuit? posted by jarthel on April 23, 2007 at 23:19:46:
You will definitely need to heatsink the current source, the heat dissiplation is (230-150)*.078 = 6.24 watts. A TO220 package is only capable of dissipating around 1.5 watts or so without a heatsink, however this is a function of the ambient temperature and allowable temperature rise of the device.I think you are on the right path using a Pimm current source, the LM417 by itself is not capable of the voltage drop, and Allen Wright even suggests to omit the 417 from his MOSFET current source for best sound (replacing with a fixed resistor).
This post is made possible by the generous support of people like you and our sponsors:
Follow Ups
- Re: what triode and transistor to use for a shunt regulator circuit? - David McGown 02:19:09 04/24/07 (0)