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Tube DIY Asylum Do It Yourself (DIY) paradise for tube and SET project builders. |
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Tube DIY Asylum Do It Yourself (DIY) paradise for tube and SET project builders. |
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In Reply to: 5K not optimal for Williamson, BUT check this out! posted by Thomas Martens on April 4, 2007 at 13:16:24:
I forgot the second stage of williamson was the split-load inverter!
What was I thinking???Anyhow, keep the driver circuit unchanged (don't delete the first
stage) except for the before mentioned elimination of the feedback
line connection, and the addition of a 470uf cap to the first stage
cathode resistor *Which you will now have to recalculate for a
single resistor OR simply parallel a 1.2K with a 470 Ohm and this
would be your cathode resistor. (Sorry, too lazy to calculate at
the moment for single R!)-T.M.
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Follow Ups
- Whoops! minor correction.... - Thomas Martens 13:25:58 04/04/07 (2)
- With all these stages, and no loop feedback... - Allen Wright 01:24:43 04/05/07 (1)
- Yep... - Thomas Martens 20:57:49 04/05/07 (0)
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