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RE: another explanation...

96.44.151.31

Good idea to go through the calculations on this assertion.

You wrote:
"Let's say we have two hypothetical gain stages. Each with a gain of 10 and having only 2nd order harmonic distortion. Let's say the percentage of 2nd order distortion is 10% (each stage).

If we apply 1 volt of 1kHz to the first stage we get 10 volts of 1kHz and 1 volt of 2khz feeding the second stage.

The second stage amplifier the 10 volts of 1kHz to give us 100 volts of 1kHz.

The second stage amplifies the 1 volt of 2kHz to give us 10 volts of 2kHz.

The second stage distorts the 1Khz and gives us 10 volts MORE of 2khz for a total of 20 volts 2kHz.

The second stage also distorts the 1 volt of 2kHz input signal, to give us 1 volt of 4kHz.

What have I missed?"

I will now edit all those lines to correct the errors, one by one:

"If we apply 1 volt of 1kHz to the first stage we get -10 volts of 1kHz (polarity inversion needs a minus sign) and 1 volt MAGNITUDE of 2khz feeding the second stage, phase not found due to not knowing the distortion transfer function completely. It could be -180 degrees, where it is likely. That means we might assume it is actually -1 volts of 2khz midband.

The second stage amplifier with -10 volts of 1kHz then gives us (1)(-10)(-10) = +100 volts of 1kHz. Note two polarity inversions for inverting common cathode stages.

The second stage amplifies and inverts the -1 volt of 2kHz to give us +10 volts of 2kHz.

The second stage distorts the 1Khz and gives us -10 volts MORE of 2khz for a total of a magnitude of (+10)+(-10) = 0 volts 2kHz!"

It gets complicated quickly when the order is increased to calculate % distortion of a single even order harmonic. But you can see that it's doing it quite well to the 2nd order in terms of cancellation.


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