In Reply to: I'm "guessing" bmotorcycle is right... posted by SteveBrown on December 9, 2006 at 05:23:58:
In this case the 300B must be able to drive the 845 into A2 and, if I understand correctly, this means it must swing the voltage required to drive the grid positive with respect to the cathode and to supply the grid with current, as the grid of the 845 will draw current when it is positive with respect to the cathode.
__________________________________________________
Boo!
This post is made possible by the generous support of people like you and our sponsors:
Follow Ups
- Re: 300B - Ivan303 09:02:06 12/10/06 (0)