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Re: Hmmm...

"See the link below for a real-world example of exactly this."

If the distortion components are buried in the noise ( < -100 dB), as in the linked example, they will **appear** to be equal in amplitude. This is more a noise spectrum than a distortion spectrum. (But then again, -108 dB and -118 dB are not particularly close in amplitude. +6dB implies double the voltage amplitude.)

"As the signal level drops in a digital system, the number of bits used to encode the signal drops. Think of a simple sine wave. When you get down to v.v. low levels, say 2-bits, the sine wave is being stored digitally as a signal with only 4 discrete levels. When this signal is converted back to analog, it will have spectral components at multiples of the original sine wave's frequency. In other words, harmonic distortion."

Since the waveform at such levels without dithering has the appearance of "square waves" the harmonic equation for square waves would likely be more-accurate- Odd harmonics of decreasing amplitude with order... But the fundamental components of the square wave could include the first few harmonics of the actual sine wave... Once again, I think there are too many variable to form a definitive equation. (I could be wrong about the "definitive equation"... I just haven't seen one derived.)

"Later in the same thread, another poster (Werner) pointed out that the signal was probably undithered and that dithering would eliminate these harmonic distortion components. That's what I'm trying to determine."

Again, it would reduce distortion components, but not eliminate them.

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  • Re: Hmmm... - Todd Krieger 17:14:49 11/10/05 (0)


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