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Re: You must mean milliohms

"Any amplifier (or any other circuit for that matter) having an internal (series)impedence (Thevenins equivalent) which is ten times the load impedence, cannot have an efficiency of delivering power to the load of more than 10%, that is 90% or more of the electrical power delivered by the power supply will be converted to heat internally."

This, of course, runs contrary to experimental fact.

The problem is that you're trying to extend the model too far. A Thevenin/Norton equivalent will allow you to predict how the source and the load will interact, but is not useful for determining efficiency of the source. Again, think of the Norton model which suggests a HIGH efficiency. And just as falsely. Do the experiment, which will convince you much more rapidly than I can.

You are correct in that using a current source amp will force you to rethink crossovers- topologies are NOT the same. And in the real world, CS amps are most useful for single-driver full-range systems. I had my first experience with them listening to Nelson Pass's Lowther-based Kleinhorn. Marvellous. I'm somewhat poorer than Nelson, so a Fostex FE166 is more my speed.

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