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Re: My apologies

So I take it that there is 200uF of capacitance in series with the output signal from the last tube in the circuit, when you bypass the output transformer. If so, there ought also to be a resistor in parallel (i.e., wired from the hot pin of the output jack to ground, altho the resistor may not actually be soldered to the output jack at all; it could physically be placed in a variety of ways). Can you tell us the value of that R? And can you tell me what "ASL" stands for?


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