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RE: Gianluca. Could you calculate a rough estimate of the B+

Posted by mqracing (M) on February 13, 2011 at 09:36:50

In Reply to: Gianluca. Could you calculate a rough estimate of the B+ posted by Bas Horneman on February 13, 2011 at 08:16:04:

Hi Bas:

you were asking;

"I don't understand how you go from the load and power to rms and then to Vpp."


let's say you have a 2 watt amp (45 tube for example) working into a 5000 ohm load (primary impedance).

first multiply watts time impedance

in this case 2 times 5000 equals 10,000

then to get the volts rms take the square root of 10,000

in this case the square root of 10,000 is 100

so your signal volts (at full power) will be 100 vrms.

peak volts is volts rms times 1.41

peak to peak volts is volts rms time 2.82


if you want to know the signal current

take the volts rms and divide by the primary impedance

in the illustrated case it would be 100 divided by 5000
which equals 20 ma rms.



MSL



Builder of MagneQuest & Peerless transformers since 1989

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