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Planar Speaker Asylum Welcome! Need support, you got it. Or share your ideas and experiences. |
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In Reply to: Re: Bi-amping 1.6s posted by andyr on October 31, 2006 at 18:38:50:
The calculation is 20*log(Vout/Vin). It's just a coincidence that the value of Vout/Vin is close to the actual value (29.0). It's rare that the max output voltage is specified -- usually you have to calculate it from the rate output at a given impedance where Vout = SQRT(watts*ohms).
IMHO passively biamping is a waste of time because you have the cruddy stock crossover and even if you upgrade the components you still have insertion losses and Rg (all the resistance in the crossover not attributible to the driver) messing up the dampening factor of your amp.I may be an egoist but at least I don't talk about other people.
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Follow Ups
- Do they use logarithms in Oz? - neolith 23:32:17 10/31/06 (1)
- Thanks, neo ... - andyr 01:12:40 11/01/06 (0)
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