In Reply to: resistor calculation posted by MikeCh on February 5, 2001 at 16:27:31:
Let me double check some values.
r here is the input impedance of the amp, correct?
f is the crossover point: 600Hz for lowpass and 1600Hz for highpass (are these the correct values?)
c is the needed cap value.So, the formulas simplify down to:
1
c(lowpass) = -------------
3768 * R(amp)and
1
c(highpass) = --------------
10048 * R(amp)With 100k input impedance these evaluate out to
c(lowpass) = 2.7E-9F = 2.7nF
c(highpass) = 9.9E-10F = 0.9nFThe value for the highpass doesn't seem too far off, but lowpass seems out of whack. I think I'm missing something here. One of my assumptions or calculations must be wrong, and after looking over it I can't figure it out. Any ideas what's going on?
Thanks for your patience.
Chia-Hao
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Follow Ups
- Re: resistor calculation - CH Chang 22:07:34 02/05/01 (2)
- Re: resistor calculation - davey 10:16:49 02/06/01 (1)
- Thanks! (nt) - CH Chang 20:50:16 02/06/01 (0)