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Hi,I want to connect a LED from my amp. The DC output from rectifier is +36V and -36V. How do I connect? +36V -> resitor -> LED -> ground or +36V ->resitor -> LED -> -36V?
And what value of resistor suitable?Besides, does the LED affact the sonic performance?
Thank you.
cktc
Follow Ups:
The resistor should go between the positive supply and the positive terminal on the diode. Take the negative diode lead down to earth.
To work out the value take the diode forward voltage from the supply voltage and divide by the diode current.
The forward voltage should be between 2-3v although 12v and 24v types are available and the current drawn is usually about 20mA. Both values vary slightly with colour of diode. Blue diodes are usally higher voltage compared to their red, yellow and green counterparts.
Therefore if using a 2v diode you get a value of about 1.6k....use the next nearest value above this which would be 1.8k to allow for valiations in voltage.
If using 12v you get about 1.2k ...again I would use 1.5k to be on the safe side.
Although some people will say that they can hear diodes or displays affecting sound quality your are unlikely to notice a difference.
You could wire this led either way. The only difference would be the series resistor would have to be twice as large when running the cathode (-) end to the -36v line as opposed to ground. The total voltage supply would then be 72 volts. 72/.020=3.6k ohm where aa the 36 volt supply would then be 36/.020=1.8k ohms. I find 20ma to be too bright so i shoot for 5ma. 72/.005=14.4k 15k would be close enough and will provide 4.8ma. 36/.005=7.2k, 7.5k would give you 4.8ma.Sparky
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