|
Audio Asylum Thread Printer Get a view of an entire thread on one page |
For Sale Ads |
24.16.182.213
In Reply to: RE: But wait: there's more... posted by Steve O on October 18, 2020 at 16:48:49
Assuming you had the correct capacitor installed....and the correct direction....this is essentially just a phantom power circuit. So the signal would couple via the capacitor and ride on top of the 9VDC on the "burn in" capacitors. So, you wouldn't damage your signal source.
But the whole concept of it is ridiculous to begin with and a waste of time.
Dave.
Follow Ups:
...behaves something like a true voltage source (approaching near zero AC impedance), it will shunt any AC signal to ground leaving only 9VDC across the caps being broken. The circuits I've seen attempting to passively superimpose an AC signal on a DC source do so by placing a large value resistor in series with the DC supply.
I think the assumption is the 9 volt battery does not have zero internal resistance. There really should be a resistor between it and the rest of the circuit.
The whole thing is a joke and "designed" by somebody who had no clue what they were doing.
Dave.
FAQ |
Post a Message! |
Forgot Password? |
|
||||||||||||||
|
This post is made possible by the generous support of people like you and our sponsors: