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In Reply to: RE: Opps and thanks posted by Frihed89 on January 31, 2017 at 01:49:42
I believe there is a cathode resistor and a large value one at that.
The current through the output tube creates more voltage at the cathode than there is at the grid.
The grid is connected to the plate of the driver tube so, in the end, it's a combination of the driver tube's plate voltage and the voltage created by the output tube's current flowing through its cathode resistor that "biases" the output tube.
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