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Re: DG, Help with Formula for Attenuation

192.193.195.25

Greg, below is a suggested configuration based on a 8k ohm series resistor and a 10k ohm DACT step attenuator as the variable shunt. If you use a different attenuator as shunt, the values below will change. Changing the series resistor within a 30% range of 10k ohm (ie. 7k to 13k ohm) is OK. But you should try to match the value of the attenuator that you use for shunt to the series resistor so that you get nice smooth attenuation steps.

SeriesShuntATTInputOutput
ResRes (db)ImpImp
80000-inf8,00024
800010-58.18,010413
800032-48.18,032499
800050-44.18,050544
800079-40.18,079598
8000126-36.28,126663
8000200-32.38,200744
8000251-30.38,251791
8000316-28.48,316845
8000398-26.58,398906
8000501-24.68,501976
8000631-22.78,6311,056
8000794-20.98,7941,149
80001,000-19.19,0001,258
80001,259-17.39,2591,385
80001,585-15.69,5851,535
80001,995-14.09,9951,715
80002,512-12.410,5121,930
80003,162-11.011,1622,191
80003,981-9.611,9812,508
80005,000-8.313,0002,892
80006,309-7.114,3093,374
80007,941-6.115,9413,965
800010,000-5.118,0004,701

I don't have the output voltage of your source or the input sensitivity of your amp (and wattage) and speakers so I don't know which range you will most likely use. The general rule is that input impedance should be 20 times that of output inpedance.

The above is what I worked out for my setup. Let meknow if you need more exact calculations


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