Home Tweakers' Asylum

Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ.

As the circuit is drawn and assuming the 9V supply...

...behaves something like a true voltage source (approaching near zero AC impedance), it will shunt any AC signal to ground leaving only 9VDC across the caps being broken. The circuits I've seen attempting to passively superimpose an AC signal on a DC source do so by placing a large value resistor in series with the DC supply.


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