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Tweaks for systems, rooms and Do It Yourself (DIY) help. FAQ.

Tricky

The idea is to force the caps to share the voltage equally. Without parallel Rs, they will share according to their leakage resistance.

If they both (assuming only 2 caps) have the same resistance there will be no problem, but how to know or measure their leakage resistance? Difficult without special equipment as the effective R can be very high indeed, especially with dialectrics like teflon or polyprop.

I always try to calculate a value which has minimum effect on the circuit in question, but which is clearly much lower than the effective leakage resistance. Something like 10megohms will usualy do the trick.


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  • Tricky - clifff 03:29:03 01/26/07 (0)


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