Tweaker's Asylum

Posted by Mart on May 14, 1999 at 05:54:46:

In Reply to: summary thus far... posted by Mart on May 12, 1999 at 12:22:58:

        +---Cp---+
        |        |
    0---+---Rp---+---Re---Le---0
        |        |
        +---Lp---+

    0-----Ln-----Rn-----Cn-----0

    0-------Rz--------Cz-------0

    where the driver is:
     Rp = Re*Qms/Qes
     Cp = Qes/(2*fs*Pi*Re)
     Lp = Re/(2*fs*Pi*Qes)

    where the conjugate(notch) is:
     Rn = ((Qes + Qms)*Re)/Qms
     Ln = (Qes*Re)/(2*fs*Pi)
     Cn = 1/(2*fs*Pi*Qes*Re)

    where the Zobel is
     Rz = Re + Rms
     Cz = Le/(Re*Rz)

Follow Ups:

• Yo JON RISCH Mart 11:48:14 5/14/99 (1)
  • FWIW, I could only reduce the 2 eqs to ... Mart 13:37:21 5/14/99 (0)