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Re: Help with rectifiers

12.78.135.120

This depends on the type of rectification and filter you use. A cap-input filter will produce a DC voltage 1.4 times the AC you use. If you use a full-wave rectifier, like a 5R4 or GZ37, or a pair of SS diodes, you will be using the two outer legs of the transformer secondary and grounding the center tap. This gets you 1.4 times the *half* secondary, in this case 400 volts. Your DC voltage would then be 560VDC, minus the drop across the rectifiers, etc. If you employ a bridge rectifier, you would use the FULL secondary and leave the center tap ungrounded, which would net 1.4 times 800, or 1120VDC, minus rectifier drop, etc.

OTOH, choke-input filters will net a DC figure .9 times the AC voltage. So again, with 400-0-400 and a full-wave rectifier, your DC would be 360. With a bridge, it would be 720. Is this clear?

Now you can get a cross between the two by using a cap-input filter with a very small input cap, like .47uF, which will limit the peak DC voltage to choke-input levels. If you increase this cap by small increments, up to about 1.5-2uF, you can increase the DC voltage output without reaching full cap-input levels. This is a neat trick you can use when you need to adjust the DC voltage somewhat. However, you will get less noise filtering than when using a full cap-input filter.

Does this help?


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  • Re: Help with rectifiers - groverg 07:18:24 10/02/00 (0)


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