50.24.38.118
This Post Has Been Edited by the Author
In Reply to: RE: update 2 posted by vinnie2 on February 18, 2019 at 13:54:06
"Well I gave that a try but I must have done something wrong because I came up with a voltage of 48vdc."
First of all, the voltage you should be measuring across the 8 ohm load resistor is ac, not dc. (You can't get dc out of a transformer.) Trying to guess what you actually meant to type, one possibility is that you meant 48v pp (that is, 48 volts peak-to-peak of the 1KHz sine wave). That would correspond to 48/( 2 * sqrt2) volts RMS, which is about 17 VRMS. This would imply a power of 36 watts.
However, there are too many uncertainties and guesses involved, with trying to estimate what you meant to type when you wrote 48vdc. Perhaps you could clarify?
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