In Reply to: RE: should i change the operating point ? posted by DAK on April 19, 2017 at 20:50:16:
If you say the B+ is 220v and using a 10K plate load resistor, dropping Va to 180, your current is (220-180)/10000 = 0.004 or 4mA
0.004 * 180 = 0.72 watts which is pushing it with a 6SL7
But the bigger problem is that a 10K load on a 6SL7 is really inefficient. The 6SL7 is a low current voltage driver, and the 10K really handicaps the swing it can develop. The resistors look like the designer of your circuit was using a 6SN7 and you dropped a 6SL7 into it.
TKs suggestions will make your amp sound a lot better.
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Follow Ups
- You might want to look again - Chip647 05:03:50 04/20/17 (2)
- RE: You might want to look again - Tre' 11:14:11 04/20/17 (0)
- I forgot the anode to anode feedback resistor - DAK 09:02:17 04/20/17 (0)