|
Audio Asylum Thread Printer Get a view of an entire thread on one page |
For Sale Ads |
70.91.92.17
In Reply to: RE: Replacing inductors posted by throwback on April 24, 2017 at 05:53:33
Making a burn-in jig for inductors is easy enough. Just take a resistor and connect it to one end of the inductor, and then connect the free ends of this series network to your amp in parallel with your speaker. I.e. one amp lead goes to the free end of the inductor, and the other amp lead goes to the free end of the resistor. You now have the equivalent of a 6-db low-pass crossover filter. The resistor value is not critical at all. It could be something in the 8 ohm to 20 ohm range, but it should be at least 10 watts. Then you can just run the amplifier with music signal. I have done this many times with resistors, capacitors and wire all hooked up to my video system and running 24/7. It should do just fine with an inductor as well.
Follow Ups:
Thanks, Salectric. A spkr mfgr buddy of mine already has such a contraption and he is going to break in all my components for 100 hours.
I appreciate your response.
FAQ |
Post a Message! |
Forgot Password? |
|
||||||||||||||
|
This post is made possible by the generous support of people like you and our sponsors: