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Hello,
Could somebody tell me in which way compression ratio shows
up in the equivalent mechanical circuit of a loudspeaker which
is put on a horn.I do simulations in Akabak en when i put a loudspeaker with a 855cm2 radiatorarea on horn which have a 400cm2 throat, it`s converting the acoustic load (horn with radiation and frontchamber) to it`s mechanical circuit with the coupler SD 855cm2 and not with a 400cm2 area. I was wondering if this is correct?
If this is correct (which i don`t think so), how could you see in it`s equivalent circuit that the horn is loaded under the heavy compression ratio?
Cheers,
Marcel
Follow Ups:
Hi Marcel,Not sure if this answers your question.
If:
Sd = driver diaphragm piston area
St = horn throat area
Zs = horn throat specific acoustical impedance
Zm = mechanical impedance of the air load on the throat side of the diaphragmThen:
Zm = Sd ^ 2 * Zs / St
Or:
Zm = (Sd / St) * Sd * Zs
Where:
Sd / St = “compression ratio”
Increasing the value of Sd for a given St and horn throat specific acoustical impedance Zs increases the values of both the compression ratio Sd / St and the mechanical impedance Zm.
Hope this helps.
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