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In Reply to: No, the output is already half once it leaves the cartridge. posted by Garth on October 3, 2006 at 22:23:40:
At least I got straighten out. I was assuming maximum power transfer since a 14 ohm impedance source driving a 14 ohm load. So now I know that it is not really the case. How do you compute the resulting voltage depending on the load values?thanks
Abe
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Follow Ups
- Alright! - amandarae 22:28:42 10/03/06 (2)
- Alright already! :-) - Garth 22:52:45 10/03/06 (1)
- Thanks! - amandarae 23:22:15 10/03/06 (0)