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In Reply to: Re: Same Set Up...Same Results! posted by amandarae on October 3, 2006 at 22:06:59:
The cartridge "produces" half the voltage of the unloaded condition. It is not a case of the "full voltage" hitting a "resistor brick wall" and being reduced.The secondary "sees" the load impedance and reflects it to the cartridge through the transformer primary. The load on/at the coils of the cartridge is X or 1/2X or whatever the transformer presents it.
There may be some good reasons (that I don't know) to put the additional parallel resistor at the preamp but that is not one of them.
Sorry. :-)
Cheers!
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Follow Ups
- No, the output is already half once it leaves the cartridge. - Garth 22:23:40 10/03/06 (3)
- Alright! - amandarae 22:28:42 10/03/06 (2)
- Alright already! :-) - Garth 22:52:45 10/03/06 (1)
- Thanks! - amandarae 23:22:15 10/03/06 (0)