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RE: balancing the plate volts and plate current




A voltage drop resistor is a resistor between the B+ and the decoupling cap.

The plate resistor is feed by the drop resistor but the value of the drop resistor is not part of the plate load because there is a the decoupling cap in place.

The decoupling cap is a AC ground point so the resistor value of the drop resistor is not part of the plate load. That is to say, the tube will not "see" the drop resistor as part of the load impedance that it is driving.

You never show everything in your schematics and that makes it hard to talk about your circuit. I can't point out what I can't see.

Tre'
Have Fun and Enjoy the Music
"Still Working the Problem"


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