In Reply to: RE: balancing the plate volts and plate current posted by vinnie2 on September 28, 2016 at 09:03:30:
A voltage drop resistor is a resistor between the B+ and the decoupling cap.
The plate resistor is feed by the drop resistor but the value of the drop resistor is not part of the plate load because there is a the decoupling cap in place.
The decoupling cap is a AC ground point so the resistor value of the drop resistor is not part of the plate load. That is to say, the tube will not "see" the drop resistor as part of the load impedance that it is driving.
You never show everything in your schematics and that makes it hard to talk about your circuit. I can't point out what I can't see.
Tre'
Have Fun and Enjoy the Music
"Still Working the Problem"
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Follow Ups
- RE: balancing the plate volts and plate current - Tre' 09:57:06 09/28/16 (12)
- Let me try again - Tre' 10:11:58 09/28/16 (11)
- RE: Let me try again - vinnie2 13:56:49 09/28/16 (10)
- RE: Let me try again - Sidewinder 18:12:36 09/28/16 (1)
- RE: Let me try again - vinnie2 18:26:38 09/28/16 (0)
- RE: Let me try again - elblanco 14:48:49 09/28/16 (1)
- RE: Let me try again - vinnie2 15:31:23 09/28/16 (0)
- RE: Let me try again - Tre' 14:45:09 09/28/16 (5)
- RE: Let me try again - vinnie2 15:26:20 09/28/16 (4)
- RE: building the proven/tested circuits ... - deathtube 667 20:02:02 09/28/16 (3)
- RE: building the proven/tested circuits ... - vinnie2 03:41:50 09/29/16 (0)
- RE: building the proven/tested circuits ... - Tre' 20:30:43 09/28/16 (1)
- RE: building the proven/tested circuits ... - vinnie2 03:43:08 09/29/16 (0)