In Reply to: RE: Not following you.... posted by Triode_Kingdom on July 25, 2015 at 15:25:20:
I don't know why I thought I could change the cathode resistor to simulate current going up (since this resistor wouldn't change unless it failed).
I did the math and found that with the 1.2K cathode resistor and 120ma of current, I would get about 6.2v at the PIC(144v at the top of cathode resistor). I don't do these manual calculations enough so I needed a slap in the face..... Seems I'm getting lazy with computers around!
Now I need to adjust the voltage divider since its a little high for the PIC I'm using.BTW, I did play around with the circuit just to see if I could simulate this as well by simulating a partially shorted winding in the OPT.
I got the same results as the manual calculation. I'll still do the manual calculation to adjust the "window" of current I'm monitoring. It's actually easier than simulating a partial short in an OPT
Thanks again for the help as always
Edits: 07/26/15
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Follow Ups
- RE: Got it now! I know, I was being hardheaded.... - deafbykhorns 15:20:05 07/26/15 (1)
- Excellent! - Triode_Kingdom 22:43:24 07/26/15 (0)