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Tube DIY Asylum Do It Yourself (DIY) paradise for tube and SET project builders. |
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Tube DIY Asylum Do It Yourself (DIY) paradise for tube and SET project builders. |
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In Reply to: RE: Not following you.... posted by deafbykhorns on July 23, 2015 at 17:44:39:
" wouldn't the higher current reduce the cathode voltage similar to me changing the cathode resistor?"Monitoring cathode voltage has nothing to do with changing the resistor. The resistor is fixed. Ohm's Law tells us how to calculate current from the resistor and voltage. Mathematically, I (current in amps) = E (voltage across the fixed resistor) / R (resistance in Ohms). The PIC needs to be programmed to convert the voltage at the cathode in accordance with this formula. Measure the voltage, divide it by the resistance, and the PIC can store the result as current.
Edits: 07/23/15 07/23/15
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Follow Ups
- RE: Not following you.... - Triode_Kingdom 19:55:57 07/23/15 (6)
- RE: Not following you.... - deafbykhorns 17:32:53 07/24/15 (5)
- RE: Not following you.... - Triode_Kingdom 22:17:47 07/24/15 (4)
- RE: Not following you.... - deafbykhorns 12:58:47 07/25/15 (3)
- RE: Not following you.... - Triode_Kingdom 15:25:20 07/25/15 (2)
- RE: Got it now! I know, I was being hardheaded.... - deafbykhorns 15:20:05 07/26/15 (1)
- Excellent! - Triode_Kingdom 22:43:24 07/26/15 (0)
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