In Reply to: Voltage Divder posted by deafbykhorns on July 20, 2015 at 18:39:02:
"current increases as voltage decreases in this circuit."
I don't see a problem with the divider, but you lost me with the above statement. The voltage drop across R4 is directly proportional to the cathode current. I'm sure you know that.
This post is made possible by the generous support of people like you and our sponsors:
Follow Ups
- RE: Voltage Divder - Triode_Kingdom 16:45:10 07/21/15 (12)
- RE: Voltage Divder - deafbykhorns 11:22:32 07/22/15 (9)
- RE: Voltage Divder - Triode_Kingdom 12:40:30 07/22/15 (8)
- RE: Not following you.... - deafbykhorns 17:44:39 07/23/15 (7)
- RE: Not following you.... - Triode_Kingdom 19:55:57 07/23/15 (6)
- RE: Not following you.... - deafbykhorns 17:32:53 07/24/15 (5)
- RE: Not following you.... - Triode_Kingdom 22:17:47 07/24/15 (4)
- RE: Not following you.... - deafbykhorns 12:58:47 07/25/15 (3)
- RE: Not following you.... - Triode_Kingdom 15:25:20 07/25/15 (2)
- RE: Got it now! I know, I was being hardheaded.... - deafbykhorns 15:20:05 07/26/15 (1)
- Excellent! - Triode_Kingdom 22:43:24 07/26/15 (0)
- RE: Voltage Divder - danlaudionut 02:59:07 07/22/15 (1)
- RE: Voltage Divder - deafbykhorns 17:21:42 07/23/15 (0)