In Reply to: RE: UTC output transformers LS-63 posted by dave slagle on April 16, 2015 at 09:16:00:
the primary inductance (self inductance) of the output transformer is in parallel with the reflected primary impedance which is the product of the turns ratio squared times the load resistance on the secondary winding.the current consumed by the primary inductance does not contribute to power reaching the secondary. It is a shunt arm.
that's why your power response (large signal response) will be down -3db when the inductive impedance of the primary equals the reflected impedance. One half of the power is diverted from the secondary load.
in the output stage the only generator we have available is the anode of the tube. It must be capable of providing the vector sum of the necessary AC signal current as well as the current consumed by the shunt arm i.e. the inductive reactance.
the exciting current can be calculated from;Iex = Ep divided by (two times pi times F times L)
MSL
Builder of MagneQuest & Peerless transformers since 1989
Edits: 04/16/15 04/16/15 04/16/15 04/16/15
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Follow Ups
- RE: UTC output transformers LS-63 - mqracing 09:38:19 04/16/15 (0)