In Reply to: running metal 6L6s in my Onix SP3? posted by gkargreen on July 27, 2014 at 16:12:49:
resistor, I can get the current flow thru the resistor, which would be the same as the current thru the plate and multiplying that current by the voltage across the plate will get me the wattage being put out by the tube, correct?
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Follow Ups
- if I measure the voltage drop across the cathode bias... - gkargreen 13:15:57 07/29/14 (9)
- RE: if I measure the voltage drop across the cathode bias... - Jim McShane 14:18:49 07/29/14 (8)
- RE: if I measure the voltage drop across the cathode bias... - gkargreen 18:09:06 07/29/14 (7)
- RE: if I measure the voltage drop across the cathode bias... - Jim McShane 09:17:37 07/30/14 (5)
- RE: if I measure the voltage drop across the cathode bias... - gkargreen 10:11:32 07/30/14 (4)
- RE: Measure your voltage on pin 5 - Russ57 08:38:55 07/31/14 (3)
- RE: Measure your voltage on pin 5 - gkargreen 08:50:17 07/31/14 (2)
- RE: -33?????? - Russ57 14:46:28 08/01/14 (1)
- RE: -33?????? - gkargreen 14:55:29 08/01/14 (0)
- RE: bias is set rather differently - Russ57 20:58:30 07/29/14 (0)