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Underlying mechanism of low H low DCR supply

Hello tube DIYer

My thoughts only.

1) LC filter is a kind of resonant circuit.

2) The rectifier current is a kind of pulsating wave --- mix of DC + 120Hz + 240Hz + 360Hz + ...so on.

The order of current amount is DC(0.9) > 120Hz > 240Hz >….

3) Maximum conduit of the current from rectifier should be higher than 120Hz and below 360Hz

4) Resonant point (lowest impedance) of LC filter should be the same maximum conduit point.

For example of ABC’s opinion
L1 60mH
C1 20u
Calculated resonant f -– 148.3 Hz
Result ---more than X 0.9 of supply voltage. It includes DC plus most part of 120Hz and some of 240Hz.

For example of traditional L input
L1 10H
C1 40u
Calculated resonant f -– 8 Hz
Result ---about X 0.9 of supply voltage. Only DC current. It removes any AC current from rectifier.

If the above hypothesis is correct, it would explain partly low H low DCR PSU, especially the role of L1, C1 in aspect of low H. The results are high voltage, excellent regulation, and transit time of this PSU.

In aspect of low DCR, it do not need any comments.

Fundamentally the amplifier is a regulator of the current from PSU. The PSU is a basic and the beginning.


Y Chung


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Topic - Underlying mechanism of low H low DCR supply - ychungmd 18:59:51 10/31/06 (51)
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