In Reply to: RE: output impedance posted by hitsware on May 5, 2014 at 16:09:42:
That is a common means that works fine for a high impedance source but in a power amp seems to be a flawed means. Wouldn't you want to see that it makes half Power rather than half voltage? That way the impedance of the circuit under test will be equal to the known impedance of the load; where half the power generated by the output section is dissipated in the load and the other half in the output section itself.
Here are the numbers from the two methodologies (the Voltage and Power paradigms).
For the M-60, the impedance of the output section is about 4 ohms, as predicted by the formula and confirmed by measurement. The Voltage method gets more like about 16-17 ohms.
The M-60 makes its maximum power into 16-17 ohms, which suggests that its actual impedance must be lower.
This post is made possible by the generous support of people like you and our sponsors:
Follow Ups
- RE: output impedance - Ralph 09:59:52 05/06/14 (8)
- RE: output impedance - cpotl 04:48:07 05/08/14 (0)
- RE: output impedance - hitsware 10:56:13 05/06/14 (6)
- RE: output impedance - cpotl 12:25:39 05/07/14 (1)
- RE: output impedance - Duke 15:29:58 05/07/14 (0)
- RE: output impedance - Ralph 12:20:27 05/06/14 (3)
- RE: output impedance - hitsware 15:34:21 05/06/14 (2)
- Looks like you are on the Voltage Paradigm - Ralph 09:23:27 05/07/14 (1)
- RE: Looks like you are on the Voltage Paradigm - hitsware 12:00:58 05/07/14 (0)