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High Efficiency Speaker Asylum Need speakers that can rock with just one watt? You found da place. |
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In Reply to: Tough crossover question (maybe) posted by bcguitar on March 2, 2015 at 15:43:48:
"For a 1st order crossover f=1/(2*pi*C*Z) so the frequency and impedance are related. For a 2nd order crossover f= 1/(2*pi*sqrt(L*C)) and so the frequency is independent of the impedance. However the Q of a 2nd order filter is dependent on the impedance (Q = Z*sqrt(C/L) )."
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Follow Ups
- RE: Tough crossover question (maybe) - djk 18:24:43 03/02/15 (8)
- RE: Tough crossover question (maybe) - bcguitar 18:44:47 03/02/15 (7)
- RE: Tough crossover question (maybe) - djk 22:49:08 03/02/15 (6)
- RE: Tough crossover question (maybe) - Alpha Al 05:11:29 03/03/15 (5)
- RE: Tough crossover question (maybe) - bcguitar 05:32:26 03/03/15 (4)
- RE: Tough crossover question (maybe) - Alpha Al 15:03:06 03/03/15 (1)
- Thanks Al and everybody. nt - bcguitar 05:11:14 03/04/15 (0)
- RE: Tough crossover question (maybe) - PeterZ 06:35:47 03/03/15 (1)
- RE: Tough crossover question (maybe) - bcguitar 06:36:53 03/03/15 (0)
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