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Bottlehead Forum Welcome! Need support, you got it. Or share you ideas and experiences. |
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In Reply to: RE: shunt regulated upgraded ParamourII 45 project starts today posted by vanofmonks on May 23, 2007 at 04:10:23:
Sure, but you probably already know them!
Voltage at the plate of the tube comes from:
** Power equals voltage squared over R
R is the OPT impedance, 3000 ohms in this case. Power is a bit less than two watts, so voltage is the square root of 2*3000 or 77.5 volts. That is RMS voltage, so multiply be 1.414 to get peak plate voltage of 109.5 volts.
Since the plate choke is at constant voltage at the top, and plate voltage below, apply Ohm's law to get the current in the choke:
Current equals voltage over impedance
Impedance is the inductive reactance, 2 * pi * frequency * inductance. The BH-6 plate choke is 40 henries, so at 30Hz this is 7540 ohms, and peak current is 109.5/7540 or 14.5mA.
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Follow Ups
- RE: shunt regulated upgraded ParamourII 45 project starts today - Paul Joppa 10:21:45 05/23/07 (1)
- RE: shunt regulated upgraded ParamourII 45 project starts today - vanofmonks 19:04:57 05/23/07 (0)
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