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What is the importance of the resistors in this RF op-amp circuit?

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Posted on September 7, 2016 at 02:22:20
candylily19@163.com
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From the TI application note RF and IF amplifiers with op amps:
The source says "The 39-pF capacitor provides peaking to compensate for some high-frequency roll-off, but better IP3 performance can be achieved by removing it and living with the roll-off." Let's just consider it left off.

What function do the resistors between the two op-amp stages serve? The choice of 50Ω50Ω makes me think of transmission lines, but this amplifier has a usable bandwidth up to around 300 MHz, so wavelength is on the order of 1 meter, significantly more than the distance between the stages (it is a dual-op-amp package), so any reflections here would be fast enough to be negligible.

Additionally, the input and the output are each terminated with 50Ω50Ω resistors. Here's it's reasonable to assume the attached cable is long enough to be considered a transmission line, and these resistors are providing termination for that line. But, why terminate at both ends? Assuming other circuits are doing the same thing, (terminating input and output), won't this serve to cut the voltage in half? This seems to be rather counterproductive for an amplifier; what's the advantage?

 

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RE: What is the importance of the resistors in this RF op-amp circuit?, posted on September 9, 2016 at 15:29:41
llwhtt
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Dynaco?

Craig

 

And one year later..., posted on September 8, 2017 at 12:28:14
Triode_Kingdom
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Location: Central Texas
Joined: September 24, 2006
The resistor in series with the output creates a 50 ohm output impedance. That's not necessary for driving cable, connecting a 50 ohm filter to a source other than 50 ohms will skew the response. Connecting a 50 ohm splitter to other than 50 ohms will degrade isolation and balance. For these reasons and others, providing a standard 50 ohm output impedance is important.





 

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