|
Audio Asylum Thread Printer Get a view of an entire thread on one page |
For Sale Ads |
50.77.201.41
In Reply to: RE: other circuit mods... posted by Michael Samra on January 18, 2017 at 16:14:53
Well Mike, Hoyer is wrong. It is a split load, where the output voltage is ~2x the input voltage. Measure grid to ground input voltage, and measure voltage cathode-anode on the finals. I'll predict with certainty you will get a ratio of 1.8:1, give or take just a wee bit.
cheers,
Douglas
Friend, I would not hurt thee for the world...but thou art standing where I am about to shoot.
Follow Ups:
If you measure g1-cathode and cathode-anode voltage, I think you'll discover the gain to be just like a plain anode load of the same load value.
cheers,
Douglas
Friend, I would not hurt thee for the world...but thou art standing where I am about to shoot.
ff you measure g1-cathode and cathode-anode voltage, I think you'll discover the gain to be just like a plain anode load of the same load value.
That I can do.
"For every complex problem there is an answer that is clear, simple, and wrong" H. L. Mencken
the most difficult bit is measuring the anode-cathode voltage. Well...it is just as hard as measuring the g1-cathode voltage since they are both not AC grounded.
Tell you what, measure anode-cathode, and g1-ground and tell me what you find.
cheers,
Douglas
you ought to be able to conduct this experiment on paper. You move the g1 up a volt, the cathode will go up around .9 volts. Since the plate winding has the same number of turns it will move the same amount, but in the opposite direction. So, anode-cathode voltage change of 1.8V for a 1V change at the input.
Friend, I would not hurt thee for the world...but thou art standing where I am about to shoot.
Post a Followup:
FAQ |
Post a Message! |
Forgot Password? |
|
||||||||||||||
|
This post is made possible by the generous support of people like you and our sponsors: