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In Reply to: RE: update 3 posted by Tre' on October 25, 2016 at 19:22:31
Sounds like my 5-25H swinging choke ought to do the trick. I will put a bleeder resistor on the last cap then. Also, when I get the other channel set up is it correct to assume the critical inductance becomes 7.5 Hy? Is there a link to the equations that covers the calculations for this? Thanks for the help!
Edits: 10/26/16 10/26/16Follow Ups:
chapter 14
Thanks. Reading that ought to keep me out of trouble and off the streets for a while!
The formula for critical inductance is,
inductance = ((voltage/current) + dcr of choke) / 1000
Most books (including the one linked by elblanco) state that one should use 2 times the calculated critical inductance.
"..when I get the other channel set up is it correct to assume the critical inductance becomes 7.5 Hy?"
No, if you draw twice the current at the same voltage then critical inductance will be one half the value originally calculated but you have to figure in the DCR of the choke so it won't be exactly one half.
The math at 130ma. current draw
475/.13=3655+100 (drc of choke just a guess)=3755/1000=3.755Hy So twice that would be 7.51Hy
The math at 260ma. current draw
475/.26=1827+100=1927/1000=1.927Hy So twice that would be 3.845Hy
Tre'
Have Fun and Enjoy the Music
"Still Working the Problem"
That's weird and counter intuitive, so it is probably true. Thanks, I will make sure I remember that when the time comes. Two more sheets for the notebook ......
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