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In Reply to: RE: Don't Know That !! posted by drlowmu on May 31, 2015 at 13:42:09
Okay, the reference to Dennis' amp had little to nothing to do with the question.Have you run a 2A3 amp with 850mV PS ripple into an efficient pair of speakers - I am curious as to what you heard or did not hear?
Regards,
91.
Edits: 06/01/15Follow Ups:
If you have 850mv of ripple on a 2.5k to 8ohm output transformer there will be 48.1mv across the speaker.
2500/8=312.5 is the impedance ratio of the output transformer.
The square root of 312.5 is 17.67 and that's the voltage step down ratio of the transformer. (it's also the winding ratio)
850mv / 17.67 is 48.1mv
48.1mv will produce a lot of sound depending on the sensitivity of the speaker.
Tre'
Have Fun and Enjoy the Music
"Still Working the Problem"
That isn't exactly correct.
The 2.5K output is in series with the Rp of the tube so you need to use ohms law to figure out the AC across the transformer. Assuming a 2K5 load and a 750R tube it works out to:
.850V/(2500+750)= 262uA of current. 262uA of current through 2500 ohms is 654mV of ripple showing up across the transformer that divided by 17.68 nets 27mv of ripple at the speaker. (still way to much)
dave
So a quick glance at the math tells me that 100-150mV of ripple is about the limit to obtain ~ 4-5mv to the speakers?
.
Have Fun and Enjoy the Music
"Still Working the Problem"
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