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In Reply to: RE: Without knowledge it won't make sense posted by Craiger56 on July 16, 2015 at 17:00:08
So... How would low frequencies make it to the HF terminals, or the high frequencies to the LF terminals without current?OK, since we're going to be pedantic and precice, what exactly do you mean by "low frequencies make it to the HF terminals"? Specifically "make it"?
Thanks.
Edits: 07/16/15Follow Ups:
"Make it" was my poor substitute for conducted, in reply to your less than ideal term "disappear".
As in, when bi-wiring low frequencies are attenuated over the entire length of high frequency cable, and high frequencies are attenuated over the entire length of low frequency cable.
Good evening
Right. It has to be over the entire length. It's the current that is being attenuated. The voltage is not attenuated until post filter. But the current is attenuated all the way back to the amplifier terminals where the bi-wire split is made.I think Dave is adding discussion about interaction between cables where the individual currents can modulate one another when separated into adjacent cables. This is complex, because we need to know about more than just the distance separating the cables, but the cable geometry including insulation thickness and turns per unit length.
If we're going that far, there are lots of details that would need to be added to the theoretical model if that specific detail were to be added, such as the individual voltage drops *across* each bi-wired cable, which would be different, since the currents going through them are also different, despite each cable having the same impedance. In that case the voltages presented to each filter input are NOT identical, albeit close.
The, introduce two different cables into the model and ALL kinds of mathematical hell breaks loose! ;)
Cheers,
Presto
Edits: 07/17/15
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