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In Reply to: RE: Burn-In track? and Demagantising ones posted by PAR on August 22, 2016 at 18:00:17
Please explain.
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It's because demagnetising tracks use a sweep tone to demagnetise using hysterisis. As the electronic crossover in an active system blocks part of the tone sent to each of the amplifiers anything in the circuit beyond the electronic crossover will not be demagnetiised.
Burn in is different as it is not necessary to maintain an uninterrupted sweep of frequencies to work.
Ah, makes sense. Thanks.
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