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I would just like some reassurance that my arithmetic concerning loading is correct.
I'm using 1678 SUTs at 1:16 and a phonopreamp with a 47.5K ohm input impedance. I want the cartridge to see a load of 150 ohms.
I took the 47.5K ohm resistors out of the phonopreamp and replaced them with 38.3K ohm resistors. Should this present a 150 ohm load to the cartridge?
This is approximately correct. The exact value (from my spreadsheet program) is 142 ohms.
Kevin Carter
K&K Audio
www.kandkaudio.com
Hey Kevin,
What formula does your spreadsheet use to calculate loading? I thought the correct formula was:
input impedance/(turns ratio x turns ratio)
In this case:
38.3K/(16*16)=149.6 ohms
How are you getting 142 ohms?
The complete formula requires that the winding resistances be taken into account. They are electrically in series with the load resistor, one directly and the other through the transformer transformed by the impedance ratio.
The spreadsheet program does take these into account.
Kevin Carter
K&K Audio
www.kandkaudio.com
Thanks, Kevin. I didn't know that the winding resistance should be taken into account. I'm planning on trying out some other loadings but would first like to use the correct calculation for my particular step up (1678). Is there a download to it somewhere? I am not using any parallel resistors as I prefer to put different values in place of the phonostage's 47K ohm loading resistor. If there's no download to a spreadsheet for my application (no parallel resistors) can you point me to the formula that takes into account the winding resistance?
Hmmm... I get 149.6 using the calculator on Hagerman's website. That's not much of a difference, though. Thanks for the reply. At least I now know I have the right idea and am in the ballpark.